Answer
$h_p=sinΦcosθ$
$h_Φ=pcosΦcosθ$
$h_θ=-psinΦsinθ$
Work Step by Step
Take the first partial derivatives of the given function. When taking partial derivative with respect to Φ, treat Φ and θ as constants, with respect to Φ, treat Φ and θ as constants, and with respect to θ, treat p and Φ as constants:
$h_p=sinΦcosθ$
$h_Φ=pcosΦcosθ$
$h_θ=-psinΦsinθ$