Answer
$f_x=ye^{xy}ln(y)$
$f_y=e^{xy}\times1/y+xe^{xy}ln(y)$
Work Step by Step
Take the first partial derivatives of the given function. When taking partial derivative with respect to x, treat y as a constant, and vice versa:
$f_x=ye^{xy}ln(y)$
$f_y=e^{xy}\times1/y+xe^{xy}ln(y)$