Answer
$(\frac{1}{\sqrt[4]{2}}, \pi/8), (\frac{1}{\sqrt[4]{2}}, 9\pi/8)$, and the pole
Work Step by Step
$sin2\theta=cos2\theta$
$\theta=\frac{\pi}{8},\frac{9\pi}{8}$
Thus the points of intersection are:
$(\frac{1}{\sqrt[4]{2}}, \pi/8), (\frac{1}{\sqrt[4]{2}}, 9\pi/8)$, and the pole
