Answer
$\lim\limits_{x \to 0^-}\csc x =\lim\limits_{x \to 0^-}\frac{1}{\sin x }=-\infty\\
(as\,x\,approach\,0\,from\,left\,\, \sin x\,\,is\,negative\,\,and\,approach\,0)
$
Work Step by Step
$\lim\limits_{x \to 0^-}\csc x =\lim\limits_{x \to 0^-}\frac{1}{\sin x }=-\infty\\
(as\,x\,approach\,0\,from\,left\,\, \sin x\,\,is\,negative\,\,and\,approach\,0)
$
