Answer
$\lim\limits_{z \to 4}\frac{z-5}{(z^2-10z+24)^2}=-\infty \\
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Work Step by Step
$\lim\limits_{z \to 4}\frac{z-5}{(z^2-10z+24)^2}=-\infty \\
(as\,z\,approach\,4\,\,the\,numerator\,(z-5)\,approach\,\,-1\,\\and\,\,\,the\,denominator\,is\,positive\,and\,approach\,\,\,0)\\
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