Answer
$\lim\limits_{\theta \to 0^+}\csc \theta =\lim\limits_{\theta \to 0^+}\frac{1}{\sin \theta }=+\infty\\
(as\,\theta\,approach\,0\,from\,left\,\, \sin \theta\,\,is\,positive\,and\,approach\,0)
$
Work Step by Step
$\lim\limits_{\theta \to 0^+}\csc \theta =\lim\limits_{\theta \to 0^+}\frac{1}{\sin \theta }=+\infty\\
(as\,\theta\,approach\,0\,from\,left\,\, \sin \theta\,\,is\,positive\,and\,approach\,0)
$
