Answer
$$-(x^2-1)^{-1/2}+C$$
Work Step by Step
Given $$\int \frac{x d x}{\left(x^{2}-1\right)^{3 / 2}}$$
Let
$$ u=x^2 -1\ \ \ \ \ \ \ \ du=2xdx$$
Then
\begin{align*}
\int \frac{x d x}{\left(x^{2}-1\right)^{3 / 2}}&=\frac{1}{2}\int \frac{ d u}{u^{3 / 2}}\\
&=-u^{-1/2}+C\\
&=-(x^2-1)^{-1/2}+C
\end{align*}