Answer
$1$
Work Step by Step
We have
$$ \lim\limits_{n \to \infty}{a_n}=\lim\limits_{n \to \infty} 2^{1/n}=2^0=1.$$
Using Theorem 1, we see that the sequence $a_n$ converges to $1$.
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 11 - Infinite Series - 11.1 Sequences - Exercises - Page 538: 39
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