Answer
$$\frac{1}{2}\tan x +c$$
Work Step by Step
Given$$\int \frac{dx}{1+\cos 2x}$$
Since $$\cos 2x=2\cos^2x-1$$
\begin{align*}
\int \frac{dx}{1+\cos 2x}
&=\int \frac{dx}{2\cos^2x}\\
&=\frac{1}{2}\int \sec^2 xdx\\
&=\frac{1}{2}\tan x +c
\end{align*}