Answer
$$ - \cos y + C$$
Work Step by Step
$$\eqalign{
& \int {\frac{{dy}}{{\csc y}}} \cr
& {\text{basic trigonometric identity csc}}\theta = \frac{1}{{\sin \theta }} \cr
& \int {\frac{{dy}}{{\csc y}}} = \int {\frac{{dy}}{{1/\sin y}}} \cr
& = \int {\sin y} dy \cr
& {\text{use integration formula from table 4}}{\text{.2}}{\text{.1}} \cr
& = - \cos y + C \cr} $$