Calculus: Early Transcendentals 9th Edition

Published by Cengage Learning
ISBN 10: 1337613924
ISBN 13: 978-1-33761-392-7

Chapter 2 - Section 2.3 - Calculating Limits Using the Limit Laws - 2.3 Exercises - Page 103: 11

Answer

$ - 13$

Work Step by Step

$$\eqalign{ & \mathop {\lim }\limits_{x \to - 2} \left( {3x - 7} \right) \cr & {\text{Evaluate the limit by using the Direct Substitution Property}} \cr & \mathop {\lim }\limits_{x \to a} f\left( x \right) = f\left( a \right) \cr & \cr & {\text{Therefore}}{\text{,}} \cr & \mathop {\lim }\limits_{x \to - 2} \left( {3x - 7} \right) = 3\left( { - 2} \right) - 7 \cr & \cr & {\text{Simplifying}} \cr & \mathop {\lim }\limits_{x \to - 2} \left( {3x - 7} \right) = - 6 - 7 \cr & \mathop {\lim }\limits_{x \to - 2} \left( {3x - 7} \right) = - 13 \cr} $$
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