Answer
$-1.25, \ or, \ -0.667$
Work Step by Step
For the equation $12x^2 +23x+10= 0$, we use the quadratic formula as follows
$$
x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a},
\\
a=12, \quad b=23, \quad c=10
.$$
That is,
$$
x=\frac{-23\pm \sqrt{23^2-4(12)(10)}}{2(12) }=-1.25, \ or, \ -0.667
.$$
