Answer
$$ 3 \pm j .$$
Work Step by Step
For the equation $x^2 - 6x + 10 = 0$, we use the quadratic formula as follows $$ x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}, \quad a=1, \quad b=-6, \quad c=10 .$$ That is, $$ x=\frac{6 \pm \sqrt{36-40}}{2 }=\frac{6 \pm 2j}{2 }= 3 \pm j .$$
