Answer
$$ 3+2j, \ or, \ 3-2j .$$
Work Step by Step
For the equation $x^2 -6x+13 = 0$, we use the quadratic formula as follows
$$ x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}, \\
a=1, \quad b=-6, \quad c=13.$$
That is,
$$ x=\frac{6 \pm \sqrt{36-4(13)}}{2 }= 3+2j, \ or, \ 3-2j .$$
