Answer
$$-j.$$
Work Step by Step
Since $j=\sqrt{-1}$, $j^2=-1$, $j^3=-j$, $j^4=1$, then by multiplying both the denominator and numerator by $j^3$, we have
$$ \frac{1}{j}= \frac{j^3}{j^4}=j^3=-j.$$
Elementary Technical Mathematics
by Nelson, Robert; Eren, Dale;
Published by
Brooks Cole
ISBN 10:
1285199197
ISBN 13:
978-1-28519-919-1
Chapter 11 - Section 11.5 - Imaginary Numbers - Exercise - Page 378: 23
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