Answer
$0.25 + 0.661j, \ or, \ 0.25 - 0.661j$
Work Step by Step
For the equation $2x^2 -x+1= 0$, we use the quadratic formula as follows
$$
x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a},
\\
a=2, \quad b=-1, \quad c=1
.$$
That is,
$$
x=\frac{1\pm \sqrt{1-8}}{2(2) }=0.25 + 0.661j, \ or, \ 0.25 - 0.661j
.$$
