Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 11 - Section 11.5 - Imaginary Numbers - Exercise - Page 378: 41

Answer

$-0.417+1.08j\ or, \ -0.417-1.08j$

Work Step by Step

For the equation $6x^2 +5x+8 = 0$, we use the quadratic formula as follows $$ x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}, \\ a=6, \quad b=5, \quad c=8 .$$ That is, $$ x=\frac{-5 \pm \sqrt{25-24(8)}}{2(6) }=-0.417+1.08j\ ~ or, \ -0.417-1.08j .$$
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