Answer
-1
Work Step by Step
Since $j=\sqrt{-1}$, $j^2=-1$, $j^3=-j$, $j^4=1$, we have
$$ j^{38}=j^{36}j^2 =-1$$
where we used the fact that $38=4\cdot 9+2$.
Elementary Technical Mathematics
by Nelson, Robert; Eren, Dale;
Published by
Brooks Cole
ISBN 10:
1285199197
ISBN 13:
978-1-28519-919-1
Chapter 11 - Section 11.5 - Imaginary Numbers - Exercise - Page 378: 21
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