Answer
both roots are imaginary.
Work Step by Step
We compare the given equation
$3x^2=4x-8$
$3x^2-4x+8=0$
To the quadratic equation:
$ax^2+bx+c=0$
We get the coefficients:
$$a= 3, \quad b=-4, \quad c=8,$$
We check the value of the discriminant, as follows
$$b^2 -4ac=16-4(3)(8) =-80.$$
Since $-80$ is negative, both roots are imaginary.
