Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 11 - Section 11.5 - Imaginary Numbers - Exercise - Page 378: 12

Answer

$$6.32 j.$$

Work Step by Step

We have $$\sqrt{-40}=\sqrt{(-1)(40)}=\sqrt{-1} \sqrt{40}=6.32 j.$$
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