Answer
Both roots are imaginary.
Work Step by Step
Since
$$a= 1, \quad b=0, \quad c=25,$$
We check the value of the discriminant, as follows
$$b^2 -4ac=0-4(1)(25) = -100$$
Since -100 is negative, both roots are imaginary.
Elementary Technical Mathematics
by Nelson, Robert; Eren, Dale;
Published by
Brooks Cole
ISBN 10:
1285199197
ISBN 13:
978-1-28519-919-1
Chapter 11 - Section 11.5 - Imaginary Numbers - Exercise - Page 378: 33
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