Answer
$1 + 1.16j, \ or, \ 1 - 1.16j
.$
Work Step by Step
For the equation $3x^2 -6x+7= 0$, we use the quadratic formula as follows
$$
x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a},
\\
a=3, \quad b=-6, \quad c=7
.$$
That is,
$$
x=\frac{6\pm \sqrt{36-84}}{2(3) }=1 + 1.16j, \ or, \ 1 - 1.16j
.$$
