Answer
$g(4)=2$
$g(0)=-2$
$g(-14)=-4$
Work Step by Step
Given: $\sqrt[3]{4x-8}$
Need to find $g(4), g(0),g(-14)$.
$g(4)=\sqrt[3]{4(4)-8}=2$
$g(0)=\sqrt[3]{4(0)-8}=-2$
$g(-14)=\sqrt[3]{4(-14)-8}=-4$
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 7 - Review Exercises - Page 576: 7
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