Answer
$2x^2y$
Work Step by Step
Simplify. $(8x^6y^3)^{\frac{1}{3}} $
Since, the power raised to a each base gets multiply such as $(ab)^n=a^nb^n$
Thus, $(8x^6y^3)^{\frac{1}{3}}=(2^3)^{\frac{1}{3}}(x^6)^{\frac{1}{3}}(y^3)^{\frac{1}{3}}$
or,$=(2)(x)^\frac{6}{3}(y)^\frac{3}{3}$
Hence, $=2x^2y$
