Answer
Not a real number
Work Step by Step
Since, $i^2=-1$ and $i=\sqrt -1=i$
Thus, $\sqrt[4]{ -16}=\sqrt[4] {16}\sqrt[4]{ (-1)}=2\sqrt i$
Hence, this is not a real number.
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 7 - Review Exercises - Page 576: 4
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