Answer
$\sqrt[6]{(x-5)^5}$
Work Step by Step
Simplify. $\sqrt[6] {x-5}\sqrt[6]{(x-5)^4}$
Thus,
As per the product rule, we have $\sqrt[n] {pq}=\sqrt[n] {p}\sqrt[n] {q}$
$\sqrt[6] {x-5}\sqrt[6]{(x-5)^4}=\sqrt[6]{(x-5)(x-5)^4}=\sqrt[6]{(x-5)^{1+4}}$
Hence, the above exponent in radical form can be written as:
$\sqrt[6]{(x-5)^5}$
