Answer
$\dfrac{3x}{a^\frac{4}{5}b^\frac{4}{5}}$
Work Step by Step
Simplify. $3x(ab)^{\frac{-4}{5}}$
Thus, $3x(ab)^{\frac{-4}{5}}=\dfrac{3x}{(ab)^{\frac{4}{5}}} $
Since, the product raised to a power implies that $(mn)^\frac{p}{q}=(m)^\frac{p}{q}(n)^\frac{p}{q}$
Hence, $3x(ab)^{\frac{-4}{5}}=\dfrac{3x}{a^\frac{4}{5}b^\frac{4}{5}}$
