Answer
$f(15)=5$
$f(4)=\sqrt 3$
$f(\dfrac{5}{2})=0$
$f(1)=\sqrt{-3}$; not a real number
Work Step by Step
Given: $\sqrt{2x-5}$
Need to find $f(15),f(4), f(\dfrac{5}{2}),f(1)$.
$f(15)=\sqrt{2(15)-5}=5$
$f(4)=\sqrt{2(4)-5}=\sqrt 3$
$f(\dfrac{5}{2})=\sqrt{2(\dfrac{5}{2})-5}=0$
$f(1)=\sqrt{2(1)-5}=\sqrt{-3}$; not a real number
