Answer
$\dfrac{1}{4}$
Work Step by Step
Simplify. $(8)^{\frac{-2}{3}}$
Thus, $(8)^{\frac{-2}{3}}=\dfrac{1}{(8)^{\frac{2}{3}}} \implies \dfrac{1}{(\sqrt[3]{8})^2}$
or, $=\dfrac{1}{(\sqrt[3]{2^3})^2}$
or, $=\dfrac{1}{2^2}$
Hence, $=\dfrac{1}{4}$
