Answer
$4x$
Work Step by Step
As per the product rule, we have $\sqrt[n] {pq}=\sqrt[n] {p}\sqrt[n] {q}$
Given: $\sqrt[3] {64x^3}$
Which can be written as: $\sqrt[3] {64x^3}=\sqrt[3] {64}\sqrt[3] {x^3}$
or, $=\sqrt[3] {4^3}\sqrt[3] {x^3}$
or, $=4x$
