Answer
$-2(x+7)$
Work Step by Step
As per the product rule, we have $\sqrt[n] {pq}=\sqrt[n] {p}\sqrt[n] {q}$
Given: $\sqrt[5] {-32(x+7)^5}$
Which can be written as: $\sqrt[5] {-32(x+7)^5}=\sqrt[5] {-32}\sqrt[5] {(x+7)^5}$
or, $=\sqrt[5] {(-2)^5}\sqrt[5] {(x+7)^5}$
or, $=-2(x+7)$
