Answer
$f(a-b)=a^2-2ab+b^2-3a+3b$
Work Step by Step
Substituting $x=a-b$ in $f(x)=x^2-3x$, then,
\begin{align*}
f(a-b)=(a-b)^2-3(a-b)
=
a^2-2ab+b^2-3a+3b
.\end{align*}
Intermediate Algebra (6th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321785045
ISBN 13:
978-0-32178-504-6
Chapter 5 - Section 5.4 - Multiplying Polynomials - Exercise Set - Page 289: 88
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