Answer
$16x^2-1$
Work Step by Step
Using $(a+b)(a-b)=a^2-b^2$ or the product of the sum and difference of like terms, the expression, $
(4x+1)(4x-1)
$, is equivalent to
\begin{array}{l}
(4x)^2-(1)^2
\\\\=
16x^2-1
.\end{array}
Intermediate Algebra (6th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321785045
ISBN 13:
978-0-32178-504-6
Chapter 5 - Section 5.4 - Multiplying Polynomials - Exercise Set - Page 289: 70
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