Chapter 5 - Section 5.4 - Multiplying Polynomials - Exercise Set - Page 289: 41

$4s^2-12s+8$

Using special products techniques, the given expression is equivalent to \begin{align*} & [(2s-3)-1][(2s-3)+1] \\\\&= (2s-3)^2-1^2 \\\\&= (2s)^2+2(2s)(-3)+(-3)^2-1 \\\\&= 4s^2-12s+9-1 \\\\&= 4s^2-12s+8 .\end{align*}