Answer
$\frac{1}{5}y^{2}-8y+60$
Work Step by Step
$(\frac{3}{5}y-6)(\frac{1}{3}y-10)$
$=(\frac{3}{5})(\frac{1}{3})y^{2}-(\frac{3}{5})(10)y-6(\frac{1}{3})y+6(10)$
$=\frac{1}{5}y^{2}-6y-2y+60$
$=\frac{1}{5}y^{2}-8y+60$
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