Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.4 - Multiplying Polynomials - Exercise Set - Page 289: 52

Answer

$-27x^{3}y^{2}+18x^{2}y^{2}-90xy^2$

Work Step by Step

Using the Distributive Property, the given expression is equivalent to \begin{align*} & -9xy^2(3x^2-2x+10) \\\\&= -27x^{1+2}y^{2}+18x^{1+1}y^{2}-90xy^2 \\\\&= -27x^{3}y^{2}+18x^{2}y^{2}-90xy^2 .\end{align*}
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