Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.4 - Multiplying Polynomials - Exercise Set - Page 289: 77

Answer

$22a^3+11a^2+2a+1$

Work Step by Step

Using $(a+b)(c+d)=ac+ad+bc+bd$ or the FOIL Method, the expression, $ (11a^2+1)(2a+1) $, is equivalent to \begin{array}{l} 11a^2(2a)+11a^2(1)+1(2a)+1(1) \\\\= 22a^3+11a^2+2a+1 .\end{array}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.