Answer
$x^4-2x^2y^2+y^4$
Work Step by Step
Using special products, the given expression is equivalent to
\begin{align*}
&
(x+y)(x-y)(x^2-y^2)
\\\\&=
(x^2-y^2)(x^2-y^2)
\\\\&=
(x^2-y^2)^2
\\\\&=
(x^2)^2+2(x^2)(-y^2)+(-y^2)^2
\\\\&=
x^4-2x^2y^2+y^4
.\end{align*}