Answer
$9x^2+6x+1$
Work Step by Step
Using $(a+b)^2=a^2+2ab+b^2$ or the Square of a Binomial, the expression, $
(3x+1)^2
$, is equivalent to
\begin{array}{l}
(3x)^2+2(3x)(1)+(1)^2
\\\\=
9x^2+6x+1
.\end{array}
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