Answer
$a=1, b=-6$ and $c=4$
Work Step by Step
Given : $4-3x=-x^{2}+3x$
Adding $x^{2}-3x$ to both sides, we obtain
$x^{2}-3x+4-3x=0$
Or $x^{2}-6x+4=0$
Comparing $x^{2}-6x+4=0$ with $ax^{2}+bx+c$, we get
$a=1, b=-6$ and $c=4$
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