Answer
The equation has one real solution.
Work Step by Step
Given: $2x^{2}-12x=-18$
$\implies 2x^{2}-12x+18=0$
Comparing $2x^{2}-12x+18=0$ with $ax^{2}+bx+c$, we see that
$a=2, b=-12$ and $c=18$.
$b^{2}-4ac=(-12)^{2}-4(2)(18)=144-144=0$.
The discriminant is equal to $0$. So, the equation has one real solution.
