Answer
The graph of $y=-x^2+x-6$ has two $x-$intercepts.
Work Step by Step
The given function is
$\Rightarrow y=x^2+5x-1$
Find the number of real solutions of $0=x^2+5x-1$
$= b^2-4ac$
Substitute $1$ for $a,5$ for $b,$ and $-1$ for $c$.
$= (5)^2-4(1)(-1)$
Simplify.
$= 25+4$
Subtract.
$= 29$
Discriminant is greater than $0$,
Hence, the equation has two real solutions.
The graph of $y=-x^2+x-6$ has two $x-$intercepts.
