Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 9 - Solving Quadratic Equations - 9.5 - Solving Quadratic Equations Using the Quadratic Formula - Exercises - Page 521: 43

Answer

$x\approx 2.19$ and $x\approx -1.94$.

Work Step by Step

The given equation is $\Rightarrow 4x^2-x=17$ Subtract $17$ from each side. $\Rightarrow 4x^2-x-17=17-17$ Simplify. $\Rightarrow 4x^2-x-17=0$ The equation is not easily factorable, adn the numbers are somewhat large. So, solve using the Quadratic Formula. We have $a=4,b=-1$ and $c=-17$ Quadratic formula. $\Rightarrow x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$ Substitute all the values into the formula. $\Rightarrow x=\frac{-(-1)\pm\sqrt{(-1)^2-4(4)(-17)}}{2(4)}$ Clear the parentheses. $\Rightarrow x=\frac{1\pm\sqrt{1+272}}{8}$ Simplify. $\Rightarrow x=\frac{1\pm\sqrt{273}}{8}$ The solutions are. $\Rightarrow x=\frac{1+\sqrt{273}}{8}$ and $x=\frac{1+\sqrt{273}}{8}$ Simplify. $\Rightarrow x\approx 2.19$ and $x\approx -1.94$.
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