Answer
$\frac{1}{4}$
Work Step by Step
$1-8x=-16x^{2}\implies 16x^{2}-8x+1=0$
Comparing $16x^{2}-8x+1=0$ with $ax^{2}+bx+c=0$, we get
$a=16$, $b=-8$ and $c=1$.
The quadratic formula is
$x=\frac{-b \pm \sqrt {b^{2}-4ac}}{2a}$
Substituting the values, we get
$x=\frac{-(-8) \pm \sqrt {(-8)^{2}-4(16)(1)}}{(2)(16)}=\frac{8\pm 0}{32}=\frac{1}{4}$
