Answer
$x\approx4.3$ and $x\approx0.7$
Work Step by Step
Comparing $x^{2}-5x+3=0$ with $ax^{2}+bx+c=0$, we get
$a=1$, $b=-5$ and $c=3$.
The quadratic formula is $x=\frac{-b \pm \sqrt {b^{2}-4ac}}{2a}$
Substituting the values, we get $x=\frac{-(-5) \pm \sqrt {(-5)^{2}-4(1)(3)}}{(2)(1)}=\frac{5\pm \sqrt {13}}{2}$
The solutions of the equation are
$x=\frac{5+\sqrt {13}}{2}\approx4.3$ and $x= \frac{5-\sqrt {13}}{2}\approx0.7$
