Answer
The equation has two real solutions.
Work Step by Step
Comparing $x^{2}-5x-3=0$ with $ax^{2}+bx+c$, we see that
$a=1, b=-5$ and $c=-3$.
$b^{2}-4ac=(-5)^{2}-4(1)(-3)=25-(-12)=37$.
The discriminant is greater than $0$. So, the equation has two real solutions.
