Answer
$x=-\frac{1}{2}$ and $x=-4$.
Work Step by Step
$2x^{2}+9x+7=3\implies 2x^{2}+9x+4=0$
Comparing $2x^{2}+9x+4=0$ with $ax^{2}+bx+c=0$, we get
$a=2$, $b=9$ and $c=4$.
The quadratic formula is
$x=\frac{-b \pm \sqrt {b^{2}-4ac}}{2a}$
Substituting the values, we get
$x=\frac{-(9) \pm \sqrt {(9)^{2}-4(2)(4)}}{(2)(2)}=\frac{-9\pm 7}{4}$
The solutions of the equation are $x=\frac{-9+7}{4}=-\frac{1}{2}$ and $x= \frac{-9-7}{4}=-4$
