Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 8 - Potential Energy and Conservation of Energy - Problems - Page 209: 85

Answer

$E= 8.82\times 10^ W$

Work Step by Step

$1m^3$ of water = $1000kg$ of water rate of energy production = $E$ mass rate ($m_r$) = $1200m^3/s \times \frac{1000kg}{1m^3}$ $m_r$ = $120000kg/s$ $m_r$ = $1.2\times 10^6kg/s$ Calculating the rate of energy produced by the generator: $E =\frac{3}{4} \times m_r \times g\times h$ $E =\frac{3}{4} \times (1.2\times 10^6kg/s) \times 9.8m/s^2\times 100m$ $E= 8.82\times 10^ W$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.