Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 8 - Potential Energy and Conservation of Energy - Problems - Page 209: 79a

Answer

$\approx 23.6KJ$

Work Step by Step

$E = U + \Delta K$ $= U + (K_f-K_i)$ $=mgh + \frac{1}{2}m(v_f-v_i)$ $=mg(dsin\theta) + \frac{1}{2}m(v_f-v_i)$ $=m(gdsin\theta + \frac{1}{2}(v_f-v_i))$ $=1500(9.8 \times (50 \times sin5^{\circ}) + \frac{1}{2}(40-30))$ $=23550J$ $\approx 23.6KJ$
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