Answer
K =2.00 J
Work Step by Step
According to the graph, to get from x = 5.00 m to x = 11.0 m, the particle will be acted on by a force $F_{3}$ = – 4.00 N from x = 8.00 m to x = 11.0 m, which is a displacement d = 3.00 m. Therefore, the force will do a work W = $F_{3}$d = (–4.00 N)(3.00 m) = –12.0 J, which represents the change in kinetic energy. Since originally K = 14.0 J, at x = 11.0 m we’ll have K = 14.0 J + (–12.0 J) = 2.00 J.
